2x^2-6x-527=0

Solution for 2x^2-6x-527=0 equation:

2x^2-6x-527=0

a = 2; b = -6; c = -527;
Δ = b2-4ac
Δ = -62-4·2·(-527)
Δ = 4252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4252}=\sqrt{4*1063}=\sqrt{4}*\sqrt{1063}=2\sqrt{1063}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{1063}}{2*2}=\frac{6-2\sqrt{1063}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{1063}}{2*2}=\frac{6+2\sqrt{1063}}{4}
$